Question

6. Find the value of x to the nearest tenth. Volume of the

cylinder is 602.88 cm3.
Volume: 602.88 cm3

Answer 1

`\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=x\\ h=12\\ V=602.88 \end{cases}\implies \begin{array}{llll} 602.88=\pi (x)^2(12)\implies \cfrac{602.88}{12\pi }=x^2 \\\\\\ \sqrt{\cfrac{602.88}{12\pi }}=x\implies 4.0\approx x \end{array}`