Answer:
Step-by-step explanation:
The first reaction is oxidation of Mn to Mn²⁺ with HNO₃:
(4H⁺ + NO₃⁻ + 3e⁻ → NO + 2H₂O) x2
(Mn → Mn²⁺ + 2e⁻) x3
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(1) 3Mn + 8H⁺ + 2NO₃⁻ → 3Mn²⁺ + 2NO + 4H₂O
The oxidation to MnO₄⁻ with IO₄⁻ is:
(2e⁻ + 2H⁺ + IO₄⁻ → IO₃⁻ + H₂O) x5
(Mn²⁺ + 4 H₂O → MnO₄⁻ + 8H⁺ + 5e⁻) x2
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(2) 2Mn²⁺ + 5IO₄⁻ + 3H₂O → 2MnO₄⁻ + 5IO₃⁻ + 6H⁺