Question

Find the equation of a line that is perpendicular to 4y-3x=1 and passes through point (-7,0).

Answer 1

-4/3x + -28/3

Explanation:

First you rearrange 4y-3x=1

y= 3/4x +1/4

then you reciprocate and change the sign the slope since you are trying to find a line perpendicular to it.

Slope(m) =-4/3

then you use the formula y-y1= m(x-x1)

y-0= -4/3 (x--7)

y= -4/3 +-28/3