Question

How many grams of water vapor would be contained in a 94.2 L cloud? (start with volume of a gas) ( molar mass of water is 18.02 g/mol)

A) 4.21 g
B) 6.29 g
C) 75.78 g
D) 117.00 g

Answer 1

C) 75.78 g

Step-by-step explanation:

Given parameters:

Volume of cloud = 94.2L

Molar mass of water = 18.02g/mol

Unknown:

Mass of water = ?

Solution:

Water is the bulk component of a cloud. To solve this problem, let us find the number of moles of the water using the relationship below first;

Number of moles of water =
`(volume of water )/(22.4\\)`

Number of moles of water =
`(94.2)/(22.4)` = 4.21moles

Now to find the number of moles;

Mass of water = number of moles of water x molar mass

= 4.21 moles x 18.02g/mole

= 75.78 g