Answer:
![E=1.56* 10^(10)J](https://img.qammunity.org/2021/formulas/chemistry/college/r6xzeurqmr5fukrxn6bw07opuk0ozzwivh.png)
Step-by-step explanation:
The energy of a photon, E, can be calculated with the Planck-Einstein equation:
![E=hf](https://img.qammunity.org/2021/formulas/physics/college/yqhzwd2c5hhi6554ecj68o32z9h0zzkgs6.png)
Where:
- h is Planck's constant 6.626×10⁻³⁴ J.s, and
- f is the frequency of the photon or electromagnetic radiation.
Substituting with your data:
![E=6.626* 10^(-34)J.s* 3.91* 10^(19)s^(-1)=2.5908* 10^(-14)J](https://img.qammunity.org/2021/formulas/chemistry/college/obhklpacs2jnp2584y6bnqmaw7puiwt9b9.png)
Now multiply by Avogadro's number to obtain the energy of one mole of photons:
![E=2.5908* 10^(-14)J* 6.022* 10^(23)=1.56* 10^(10)J](https://img.qammunity.org/2021/formulas/chemistry/college/dgq9ivpmfa1j25pwz22afo481y1fu2hpoh.png)