Given:
Two similar figures.
Solution:
Part a:
ΔABC and ΔA'B'C' are similar.
Similarity statement:
If two triangles are similar, then the corresponding sides are in proportion.
![$(A B)/(A^(\prime) B^(\prime)) = (6)/(24) =(1)/(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/jqos1bke88vs68i3g0b6j1k41tqwxcd41p.png)
![$(BC)/(B^(\prime) C^(\prime)) = (12)/(48) =(1)/(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/pzf3q1e2fw1u0ritwqhctflvo2bl5ij8dt.png)
![$(CA)/(C^(\prime) A^(\prime)) = (15)/(60) =(1)/(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/jk0slgc1rbo431exa5kw0xrf682o0pm2bn.png)
The sides are in the same ratio. Therefore the two triangles are similar.
Part b:
The sides of A'B'C' are greater than the original image ABC.
Therefore, the dilation A'B'C' is an enlargement.
Part c:
Scale factor:
![$K =\frac{\text {Side length of image }}{\text {Side length of original }}](https://img.qammunity.org/2021/formulas/mathematics/high-school/p54ycq3ly4im0p2tnibhwnwmfybtt0jyo4.png)
![$K =(A^(\prime)B^(\prime))/(AB)](https://img.qammunity.org/2021/formulas/mathematics/high-school/pj47ryzy0kaznr1ymnyuci8wv9q7pyzitu.png)
![$K =(24)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/5w1393otolq3qnj5nijyza3pid5ziwa6xw.png)
K = 4
Scale factor = 4
K > 1
Therefore the image of the dilation is enlargement.