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If 200.0 dm3 (L) of propane are burned at STP, what volume of carbon dioxide is formed at STP? C3H8 + O2 CO2 + H2O

1 Answer

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Answer:

604.13L

Step-by-step explanation:

Given parameters:

Volume of propane = 200dm³ or 200L

Unknown:

Volume of carbon dioxide formed = ?

Solution:

The reaction equation is given as;

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

The above is the balanced reaction equation.

Let us solve from the known to the unknown;

The known here is propane and unknown is carbon dioxide

At STP;

Number of moles of propane =
(volume of gas )/(22.4) =
(200)/(22.4) = 8.93moles

From the balanced reaction equation;

1 mole of propane gives 3 moles of carbon dioxide;

8.93 moles of propane will produce; 3 x 8.93 = 26.97moles

Now,

Volume of carbon dioxide = number of moles x 22.4

= 26.97 x 22.4

= 604.13L

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