128k views
2 votes
Given P(A)=0.33, P(B)=0.6 and P(A∩B)=0.248, find the value of P(A∪B), rounding to the nearest thousandth.

1 Answer

2 votes

Answer:

The value of P(A ∪ B) is 0.682 to the nearest thousandth

Explanation:

The addition rule of probability is:

P(A ∪ B) = P(A) + P(B) - P(A ∩ B), where P(A ∪ B) is probability A or B , P(A ∩ B) is probability A and B

∵ P(A) = 0.33

∵ P(B) = 0.6

∵ P(A ∩ B) = 0.248

- Substitute these values in the rule above

∴ P(A ∪ B) = 0.33 + 0.6 - 0.248

∴ P(A ∪ B) = 0.682

The value of P(A ∪ B) is 0.682 to the nearest thousandth

User Mike Andrianov
by
6.2k points