Question

a 100g sample of material requires 5104.5 joules of heat energy to raise its temperature from 20 degrees Celsius to 80 degrees Celsius. what is the specific heat capacity of the material?

Answer 1

The specific heat of the material is 0.851 J/g°C

Step-by-step explanation:

Step 1: Data given

Mass of the sample = 100 grams

Amount of heat required = 5104.5 Joules

Initial temperature = 20.0°C

Final temperature = 80.0 °C

Step 2: Calculate the specific heat of the material

Q = m* c¨* ΔT

⇒with Q = the amount of energy = 5104.5 J

⇒with m = the mass of the material = 100 grams

⇒with c = the specific heat of the material = TO BE DETERMINED

⇒with ΔT = the change of temperature = T2 - T1 = 80.0 °C - 20.0 °C = 60.0 °C

5104.5 = 100 * c * 60

c = 5104.5 / (100*60)

c = 0.851 J/g°C

The specific heat of the material is 0.851 J/g°C

Answer 2

Answer: 0.85075J/g.K

Step-by-step explanation:

Mass of the material = 100g

Energy (Q) = 5104.5J

T1 = 20°C = 293K

T2 = 80°C = 353K

Formula for heat energy (Q) = mc ∇T

Q = mc∇T

∇T = T2 - T1

∇T = 353K - 293K = 60K

Q = mc∇T

C = Q / m∇T

C = (5104.5) / (100 * 60)

C = 0.85075 J/gK

The specific heat capacity of the material is 0.85075J/gK.