Question

C3H8+5O2 -> 3CO2+4H2O How many moles of CO2 will be produced from 97.0 g of C3H8, assuming O2 is available in excess?

Answer 1

6.63moles

Step-by-step explanation:

Given parameters:

Mass of C₃H₈ = 97g

Unknown:

Number of moles of CO₂ = ?

Solution:

Let us write the balanced reaction equation;

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

To solve this problem, we have to work from the known to the unknown. The known here is C₃H₈.

Since the problem suggested that O₂ is excess, C₃H₈ is the limiting reactant that will determine the amount of product formed.

First find the number of moles of C₃H₈;

Number of moles of C₃H₈ =
`(mass)/(molar mass)`

Molar mass of C₃H₈ = 3(12) + 8(1) = 44g/mol

Number of moles of C₃H₈ =
`(97)/(44)` = 2.21moles

From the balanced reaction equation;

1 mole of C₃H₈ will produce 3 moles of CO₂;

2.21 moles of C₃H₈ produces (2.21 x 3)moles of CO₂ = 6.63moles