Final answer:
The specific gravity of the other liquid is calculated using the object's apparent mass changes in water and the unknown liquid. By applying the principle of Archimedes and the density of water, we determine the specific gravity to be approximately 0.7176.
Step-by-step explanation:
The specific gravity of a substance is the ratio of the density of that substance to the density of water. To find the specific gravity of the other liquid in the given problem, we use the concept that an object submerged in a fluid seems to lose an amount of weight equal to the weight of the fluid it displaces. This is known as the principle of Archimedes' principle.
The mass of the object in air is given as 0.0832 kg. Its apparent mass in water is 0.0673 kg, which means the water displaced has a mass of 0.0832 kg - 0.0673 kg = 0.0159 kg. The apparent mass of the object in the other liquid is 0.0718 kg, meaning the other liquid displaced has a mass of 0.0832 kg - 0.0718 kg = 0.0114 kg.
The density of water at 4.00°C is approximately 1000 kg/m³. To calculate the density of the other liquid, we would divide the mass of the displaced liquid by the volume of the displaced water (since they are equal in volume). So, density of the other liquid (p_liquid) = mass of the displaced liquid / volume of the displaced water.
Since specific gravity is the ratio of the density of the substance to the density of water, we can calculate the specific gravity of the other liquid (SG_liquid) using the ratio of their masses, because the volume cancels out. Therefore, SG_liquid = (mass of liquid displaced by the object) / (mass of water displaced by the object) = 0.0114 kg / 0.0159 kg ≈ 0.7176.
Hence, the specific gravity of the other liquid is approximately 0.7176.