Question

What are the zeros of the quadratic function F(x)=6x^2+12x-7

Answer 1

x = -1 + sqrt(78)/6

x = -1 - sqrt(78)/6

Explanation:

Zeros are the x-values where the function is 0

f(x) = 0

6x² + 12x - 7 = 0

a = 6, b = 12, c = -7

Using Quadratic formula:

x = [-12 +- sqrt(12² - 4(6)(-7)]/2(6)

x = [-12 +- sqrt(312)]/12

x = [-12 + 2sqrt(78)]/12

x = -1 +- sqrt(78)/6