Question

Question 1 of 10

2 Points
What is the magnitude of the electric field at a point 0.0075 m from a 0.0035
C charge?
Use E-ka and k – 9.00 10° N.m/c?.
O A. 4.2x 10°N
O B. 1.9 × 1010
O c. 5.6 × 101N
O D. 5.5 - 1012N
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Answer 1

C. 5.6 × 10^11 N/C

Step-by-step explanation:

The electric field
`E` at a distance
`R` from a charge
`Q` is given by

`E = k(Q)/(R^2)`

where
`k = 9*10^9Nm/C` is the coulomb's constant.

Now, in our case

`R = 0.0075m`

`Q = 0.0035C`;

therefore,

`E = (9*10^9)(0.0035C)/((0.0075m)^2)`

`\boxed{E = 5.6*10^(11)N/C.}`

which is choice C from the options given (at least it resembles it).