Given:
The given equation of line is
![y=(1)/(2)x-2](https://img.qammunity.org/2021/formulas/mathematics/high-school/8bebc7qjc3nc910odza6mcy5mp0gxbvwkn.png)
The line passes through the point (-8,1)
We need to determine the equation of the line parallel to the line
![y=(1)/(2)x-2](https://img.qammunity.org/2021/formulas/mathematics/high-school/8bebc7qjc3nc910odza6mcy5mp0gxbvwkn.png)
Slope:
Since, the lines are parallel, the slope of the line is given by
![m=(1)/(2)](https://img.qammunity.org/2021/formulas/mathematics/college/ucw89inmlv3xv98exbt8pzfpuwz4d9umwf.png)
Hence, the slope is
![m=(1)/(2)](https://img.qammunity.org/2021/formulas/mathematics/college/ucw89inmlv3xv98exbt8pzfpuwz4d9umwf.png)
Equation of the line:
The equation of the line can be determined using the formula,
![y-y_1=m(x-x_1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ks7lzc9jj3emt3ptrdvrvr0uzhz4c0qyo5.png)
Substituting the point (-8,1) and the slope
in the above formula, we get;
![y-1=(1)/(2)(x+8)](https://img.qammunity.org/2021/formulas/mathematics/high-school/3le5n8tkhjt1stpj8qg0zqvub6hz3zp2q3.png)
![y-1=(1)/(2)x+4](https://img.qammunity.org/2021/formulas/mathematics/high-school/ha462tws6yjz20smy6njxi0je48tg5ph8y.png)
![y=(1)/(2)x+5](https://img.qammunity.org/2021/formulas/mathematics/high-school/osozxv1sirertxz6mfdcw0wwe9k4m7hl6q.png)
Thus, the equation of the line is
![y=(1)/(2)x+5](https://img.qammunity.org/2021/formulas/mathematics/high-school/osozxv1sirertxz6mfdcw0wwe9k4m7hl6q.png)
Hence, Option C is the correct answer.