Question

What is the concentration of a base with a pOH of 12?

Answer 1

Answer: 1 x 10^-12 M

Step-by-step explanation:

pOH is the negative logarithm of hydroxide ion concentration in a base.

Mathematically, pOH is expressed as

pOH = -log(OH-)

where OH- is hydroxide ion concentration

So, 12 = -log(OH-)

(OH-) = Antilog (-12)

(OH-) = 1 x 10^-12 M

Thus, the concentration of the base is 1 x 10^-12 M