Answer:
The speed of the current is 7 miles per hour.
Explanation:
Let x represent speed of the current.
We have been given that a motorboat maintained a constant speed of 11 miles per hour relative to the water in going 18 miles upstream and then returning.
The speed of motorboat while going upstream would be
.
The speed of motorboat while going downstream would be
.
![\text{Time}=\frac{\text{Distance}}{\text{Speed}}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/a2l4re6nbbh9cnvpqhskispmk2h6qzd0k6.png)
Time taken while going upstream would be
.
Time taken while going downstream would be
.
Now we will compare sum of both times with total time 5.5 hours and solve for x as:
![(18)/(11-x)+(18)/(11+x)=5.5](https://img.qammunity.org/2021/formulas/mathematics/high-school/k9u06wi1xgb1kyrob2o1u6hvous5r3am6q.png)
![(18(11+x))/((11-x)(11+x))+(18(11-x))/((11-x)(11+x))=5.5(11-x)(11+x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qvq0a992eg7abfiiqfzeyii61v0lcmy9wc.png)
![198+18x+198-18x=5.5(11-x)(11+x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ngzzc97yod1dtydihgojaobt4w0n1c0tj1.png)
![396=5.5(121-x^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/8war25uqn2n3w8tsz9ay91l0cnqbzh4wmd.png)
![396=665.5-5.5x^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/zh734wi7u6tehb0ljnz5subrt1gi6fql6e.png)
![665.5-5.5x^2=396](https://img.qammunity.org/2021/formulas/mathematics/high-school/feh9bwh7v42brgxlj06rfe0284jc3icnd0.png)
![665.5-665.5-5.5x^2=396-665.5](https://img.qammunity.org/2021/formulas/mathematics/high-school/jz0f1qx76hpc7qj3uxbahi1g8s5syh8cgb.png)
![-5.5x^2=-269.5](https://img.qammunity.org/2021/formulas/mathematics/high-school/1f855njucnt7dqj84e5auu880w6cyrxanp.png)
![(-5.5x^2)/(-5.5)=(-269.5)/(-5.5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/78si3vrg063wjcdw8tvgmkw41s80aspdeh.png)
![x^2=49](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bqelw7op6bgjs3l7ykfylur3fvalzqz88j.png)
Take positive square root of both sides:
![√(x^2)=√(49)](https://img.qammunity.org/2021/formulas/mathematics/high-school/3odp3av3blvhg7ajkjvhybkpsolor3vgmb.png)
![x=7](https://img.qammunity.org/2021/formulas/mathematics/high-school/2bnkqxj7yd0fo7vi8japxxe1irbgu1f8vb.png)
Therefore, the speed of the current is 7 miles per hour.