Question

A 80 mW laser beam is polarized horizontally. It then passes through two polarizers. The axis of the first polarizer is oriented at 30∘ from the horizontal, and that of the second is oriented at 60∘ from the horizontal.

Answer 1

When light passes through polarizers, its intensity is reduced and its polarization direction may change.

Step-by-step explanation:

When light passes through polarizers, its intensity is reduced and its polarization direction may change. In this case, the laser beam starts with an intensity of 80 mW and is polarized horizontally. The first polarizer is oriented at 30∘ from the horizontal, which means the laser beam will experience a reduction in intensity and its polarization direction will shift towards 30∘ from the horizontal. The second polarizer is oriented at 60∘ from the horizontal, so the laser beam will again experience a reduction in intensity and its polarization direction will shift further towards 60∘ from the horizontal.

Answer 2

The E(incident) for the first polarizer is E(incident)=-76.1930384332

The E(incident) for the second polarizer is E(incident)=12.340115991

Step-by-step explanation:

Solving the problem:

Given

Transmitted data = 80 mW

First polarizer= 30 degree

Second polarizer= 60 degree

We have the formula,

E (transmitted) = E (incident)cos()

1. Through the first polarizer

E (transmitted) = E (incident)cos()

80=E(incident) cos(60 degree) (according to law subtract the given degree with 90 degree).

Then,

E(incident)=E(transmitted) cos()

E(incident) =80×cos 60 degree

E(incident)=-76.1930384332

The E(incident) for the first polarizer is E(incident)=-76.1930384332

2. Through the first polarizer

We have the formula,

E (transmitted) = E (incident)cos()

80=E(incident) cos(30 degree) (according to law subtract the given degree with 90 degree).

Then,

E(incident)=E(transmitted) cos()

E(incident) =80×cos 30 degree

E(incident) =12.340115991

The E(incident) for the second polarizer is E(incident)=12.340115991