Answer:
b. False
Explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so

Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
If he desires a 90 percent confidence interval estimate and wishes to have a margin of error of 1 minute, the required sample size will be
Sample size of n when
. So





Rouding up, 44.
Approximately 143.
False