Question

9-1. Assume that an average SNMP response message is 100 bytes long. Assume that a manager sends 400 SNMP Get commands each second. a) What percentage of a 100 Mbps LAN link’s capacity would the resulting response traffic represent? Answer : b) What percentage of a 1 Mbps WAN link would the response messages represent? c) What are the management implications of your answers?

Answer 1

a) 0.32%

b) 32%

c) Mbps WAN link is of more benefit

Step-by-step explanation:

Average SNMP response message = 100 bytes

Avere message for each second when manager sends 400 SNMP

: 400 SNMP per second * 100 bytes = 40000 bytes per second = 40000Bps

To convert byte to bits, We have 1 byte = 8 bits

Therefore, 40000Bps = 40000 * 8 = 320 Kbps

a) Calculating the percentage of a 100 Mbps LAN link’s capacity

100 Mbps = 100000Kbps

320 Kbps is what percent of 100000Kbps =
`(320)/(100000)` * 100 = 0.32%

So the resulting response traffic would represent 0.32% of a 100 Mbps LAN link’s capacity.

b) Calculating the percentage of a 1Mbps LAN link’s capacity

1Mbps = 1000Kbps

320 Kbps is what percent of 1000Kbps =
`(320)/(1000)` * 100 = 32%

So the resulting response messages would represent 32% of a 1Mbps LAN link’s capacity.

c) When we are using the 1 Mbps WAN link, we use 32% of its speed to response the message as opposed to 100 Mbps LAN link that uses just 0.32%. This means the 1 Mbps WAN link uses more bandwith than the 100 Mbps LAN link. Therefore the management implication is that it is better to use the 1 Mbps WAN link has it has more benefits.