Question

Suppose two chemical reactions are linked together in a way that the O2 produced in the first reaction goes on to react completely with Mg to form MgO in the second reaction. Reaction one: 2 KClO3 → 3 O2 + 2 KCl Reaction two: 2 Mg + O2 → 2 MgO If you start with 4 moles of KClO3, how many moles of MgO could eventually form

Answer 1

Numbe of mole of MgO form=12

Step-by-step explanation:

First calculate the number of mole of
`O_2` produced from 4 mole of
`KCLO_3`

Balance the first reaction:

`2KClO_3 \rightarrow 3 O_2 + 2 KCl`

from the above balanced reaction it is clearly that,

by unitry method,

2 mole of
`KCLO_3` produced 3 mole of
`O_2`

1 mole of
`KCLO_3` produced 1.5 mole of
`O_2`

from 4 mole of
`KCLO_3`
`4* 1.5` mole of
`O_2` produced

hence we have 6 mole of
`O_2` and this total oxygen will react with Mg

Balance the second reaction:

`2Mg + O_2 \rightarrow 2 MgO`

since produced oxygen in first reaction is reacted completely with Mg means Mg is given in excess quantity,

From the second balanced reacion it is clearly that,

1 mole of
`O_2` produced 2 Mole of MgO

hence 6 mole of
`O_2` will produce 12 mole of MgO

Numbe of mole of MgO form=12