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If a spring has a spring constant of 0. 5 N/m and it is stretched 0. 5 m, what is the force

of the spring?

1 Answer

6 votes

Answer:

0.25N

Step-by-step explanation:

k=0.5N/m

e=0.5m

f=?

were k=spring constant

e=extension

F=force

According to hooks law,

f=ke

f=0.5x0.5 =0.25 N

User ThomasThiebaud
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