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A magnetic B field of strength 0.9 T is perpendicular to a loop with an area of 3 m2. If the area of the loop is reduced to zero in 0.5 s, then what is the magnitude of the induced emf voltage?

User Havogt
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1 Answer

7 votes

Answer:

The magnitude of induced emf is 5.4 V

Step-by-step explanation:

Given:

Magnetic field
B = 0.9 T

Area of loop
\Delta A = 3
m^(2)

Time take to reduce loop to zero
\Delta t = 0.5 sec

To find induced emf we use faraday's law,

Induced emf is given by,


\epsilon = -(\Delta \phi)/(\Delta t)

Here minus sign shows lenz law, for finding magnitude of emf we ignore it.

Where
\phi = B\Delta A

Put the value of flux and find induced emf,


\epsilon = (B\Delta A)/(\Delta t)


\epsilon = (0.9 * 3)/(0.5)


\epsilon = 5.4 V

Therefore, the magnitude of induced emf is 5.4 V

User NSP
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