Question

At equilibrium, both the forward reaction and the reverse reaction occur simultaneously and at the same rate. Since the rates are the same, the concentrations of the reactants and products do not change. An equilibrium constant expression can be developed, which is a mathematical expression indicating the relationship between the reactants and the products. For reactions with gases, the value of Kp can be determined using the pressures of each substance to the appropriate power. The values of Kc and Kp are related by the equation, Kp = Kc(RT)n. At 298 K, Kc = 18.3 for the following reaction. What is the value of K(p)?

C₄(s) + 4 O₂(g) ⇌ 4 CO₂(g)

Answer 1

The value of the gas equilibrium constant Kp is 18.3

Step-by-step explanation:

Step 1: Data given

Kp= Kc(RT)^Δn

Temperature = 298 K

Kc = 18.3

Step 2: The balanced equation

C₄(s) + 4 O₂(g) ⇌ 4 CO₂(g)

Step 3: Calculate Kp

Kp= Kc(RT)^Δn

⇒with Kp = the gas equilibrium constant = TO BE DETERMINED

⇒with Kc = the equilibrium constant = 18.3

⇒R = the gas constant = 0.08206 L* atm/mol*K

⇒T = the temperature = 298 K

⇒Δn = mol gas phase product – mol gas phase reactant = 4-4 =0

Kp = 18.3 * (0.08206*298)^0

Kp = 18.3 * 1

Kp = 18.3

The value of the gas equilibrium constant Kp is 18.3