Answer:
The magnitude of induced emf is 0.122 V
Step-by-step explanation:
Given:
Number of turns

Magnetic field
T
Radius of coil
m
Change in time
sec
For finding the magnitude of induced emf,
According to the faraday's law,

Where
magnetic flux

Where
area of coil
For finding magnitude we neglect minus sign,


V
Therefore, the magnitude of induced emf is 0.122 V