Question

wire carrying a current of 1.85 A is bent into the shape of a square loop of side length 9.26 cm and is placed in the xy-plane. What is the torque on the wire loop if there is a uniform magnetic field of 0.259 T pointing in the +z direction

Answer 1

There is no torque (τ = 0)

Step-by-step explanation:

The torque is acting on a current carrying loop. When it is placed in a magnetic field B, the expression is the follow:

τ = I*A*B*cosθ

Due the field B acting along the +z direction, and xy-plane, it is perpendicular at coil. Thus, θ = 90°, cos90 = 0, then:

τ = 0, there is no torque with this condition

Answer 2

0.0041 Nm

Step-by-step explanation:

Parameters given:

Current, I = 1.85 A

Length of side of the square, L = 9.26 cm = 0.0926 m

Magnetic field, B = 0.259 T

The magnetic torque on the loop is given as:

τ = N * I * A * B

Where N = number of turns = 1

I = current

A = area of the loop = L * L = 0.0926²

B = magnetic field

We're told that current is acting on a perpendicular axis to the magnetic field.

Therefore:

τ = 1 * 1.85 * 0.0926² * 0.259

τ = 0.0041 Nm

The magnetic torque is 0.0041 Nm.