Question

Stock solutions of nitric acid have concentration of 16.0 M. What volume of stock solution is needed to prepare 2.00 L of 2.00 M solution of nitric acid by dilution with water?

500 mL
125 mL
250 mL
32.0 mL
62.5 mL

Answer 1

250 mL

Step-by-step explanation:

These are the variable one has to have in mind:

`C_1` = 16 M

`C_(2)` = 2 M

`V_(2)` = 2 L = 2000 mL

Note: C = concentration; V = volume; subscript 1 = stock solution; subscript = 2 = dilution.

What we have to solve is for
`V_(1)`

Use the following equation:

`C_(1)` x
`V_(1)` =
`C_(2)` x
`V_(2)` ⇒
`V_(1)` =
`(2M x 2000 mL)/(16M)` ⇒
`V_(1)` = 250 mL