Question

Find the value of x in the triangle below

Answer 1

`\usepackage\\\begin{document}x = 8`

Explanation:

Hello Ivan7882!

The Pythagorean Theorem is L^2 + L^2 = H^2

Since the side across from the right angle is 10, that is our hypotenuse. The other leg is 6.

`\usepackage\begin{document}10^2 = 100, 6^2 = 36. 100 - 36 = 64. √(64) = 8. \\{\fontfamily{qcr}\selectfont}\end{document}`

Thus, our final answer is
`$\boxed{8}$`

Answer 2

x=8

Explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

6^2 + x^2 = 10^2

36+ x^2 = 100

Subtract 36 from each side

36-36 + x^2 = 100-36

x^2 = 64

Take the square root of each side

sqrt(x^2) = sqrt(64)

x = 8