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A discus thrower (arm length 1.1 m) starts from rest and begins to rotate counterclockwise with a constant angular acceleration of 1.7 rad/s2. (a) How many radians of angle does it take for the discus thrower's angular velocity to reach 5.7 rad/s

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Answer:


\Delta \theta = 9.556\,rad

Step-by-step explanation:

The change in angular position can be found from this formula:


\omega^(2) = \omega_(o)^(2) +2\cdot \alpha \cdot \Delta \theta


\Delta \theta = (\omega^(2)-\omega_(o)^(2))/(2\cdot \alpha)


\Delta \theta = ((5.7\,(rad)/(s) )^(2)-(0\,(rad)/(s) )^(2))/(2\cdot (1.7\,(rad)/(s^(2)) ))


\Delta \theta = 9.556\,rad

User Ben Woodall
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