Question

To answer this question, you may reference the Metabolic Map.

Select the steps of glycolysis in which ATP is produced.

a. 1,3-bisphosphoglycerate → 3-phosphoglycerate

b. phosphoenolpyruvate → pyruvate

c. glyceraldehyde 3-phosphate + 1,3-bisphosphoglycerate

d. glucose + glucose 6-phosphate

e. fructose 6-phosphate → fructose 1,6-bisphosphate

Suppose 13 glucose molecules enter glycolysis. Calculate the number of inorganic phosphate molecules required as well as the number of pyruvate molecules produced.

Pi =

Pyruvate =

Answer 1

Answer: Steps which produces ATP are a and b; Pi = 36 and Pyruvate = 36

Step-by-step explanation: Glycolysis is a metabolic process that breaks down glucose to extract energy for the cell. It has 10 steps and in the end, produces 2 pyruvate molecules, 4 ATPs and 2 NADH.

The production of ATP occurs when 1,3-bisphosphoglycerate is producing 3-phosphoglycerate and when phosphoenolpyruvate produces pyruvate.

So, for the question, a and b are the right alternatives.

Inorganic phosphate molecules (Pi) are ions liberated when ATP liberates energy and transforms into ADP.

In Glycolysis, 1 glucose uses 2 Pi, therefore:

13 glucoses uses 13*2 = 36 Pi.

As said above, 1 glucose produces 2 pyruvate molecules. So,

13 glucose produces 13*2 = 36 Pyruvate molecules.

In Glycolysis, for 13 glucose molecules, it is used 36 Pi and is produced 36 pyruvate.