Question

A coil having 300 turns and a radius of 2.0 cm carries a current of 1.0 A. If it is placed in a uniform 3.0 T magnetic field, find the torque this magnetic field exerts on the coil if the normal to the plane of the coil is oriented

Answer 1

The torque this magnetic field exerts on the coil is 1.131 N.m

Step-by-step explanation:

Given;

Number of turns, N = 300 turns

Radius of coil, r = 2.0 cm = 0.02 m

Current in coil, I = 1.0 A

Magnetic field strength, B = 3.0 T

Torque exerted by this magnetic field is given as;

τ = N(μ x B)

Where;

μ is dipole moment

B is Magnetic field strength

N is the number of turns of the coil

μ = IA

where;

I is the current in the coil

A is the area of the coil

τ = NIABSinθ

Substitute the given values and calculate τ

τ = 300 x 1 x (π x 0.02²) x 3 x sin90

τ = 1.131 N.m

Therefore, the torque this magnetic field exerts on the coil is 1.131 N.m