Answer:
![f = (299790000 (m)/(s))/(3.03 m)= 9890594.06 Hz](https://img.qammunity.org/2021/formulas/mathematics/college/mxxhfv5gdhf79v0y9sdkweqfyhmd8qyt7k.png)
And if we convert to megahertz we got:
![9890594.06 Hz *(1MHz)/(10^6 Hz)= 98.9 MHz](https://img.qammunity.org/2021/formulas/mathematics/college/xov60end31k6bwapm3isjdurn2w11hpdgj.png)
Explanation:
For any mechanical wave we have the following general relationship:
![v = \lambda f](https://img.qammunity.org/2021/formulas/physics/college/ub527k4d2ksyn273bkmfqtwcak2tpq6rsx.png)
where:
v represent the speed of the wave = 299790000 m/s
represent the wavelength for the radio station
f represent the frequency of interest
If we solve for the frequency we got:
![f = (v)/(\lambda)](https://img.qammunity.org/2021/formulas/physics/college/7p1yeal093hcwppycaahtfad4wqky8ywod.png)
And replacing the values we got:
![f = (299790000 (m)/(s))/(3.03 m)= 9890594.06 Hz](https://img.qammunity.org/2021/formulas/mathematics/college/mxxhfv5gdhf79v0y9sdkweqfyhmd8qyt7k.png)
And if we convert to megahertz we got:
![9890594.06 Hz *(1MHz)/(10^6 Hz)= 98.9 MHz](https://img.qammunity.org/2021/formulas/mathematics/college/xov60end31k6bwapm3isjdurn2w11hpdgj.png)