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The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars. If the total amount of money received for the tickets was $134000, how many of each kind of ticket were sold

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Answer:

1100 field-side tickets and 4500 end-zone tickets.

Explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:


x+y=5600...(1)


y=5600-x...(1)

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be
40x and cost of y end-zone tickets would be
20y.

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:


40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:


40x+20(5600-x)=134000


40x+112000-20x=134000


20x+112000=134000


20x+112000-112000=134000-112000


20x=22000


(20x)/(20)=(22000)/(20)


x=1100

Therefore, 1100 field side tickets were sold.

Upon substituting
x=1100 in equation (1), we will get:


y=5600-1100


y=4500

Therefore, 4500 end-zone tickets were sold.

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