Question

Calculate the percent dissociation of 4-chlorobutanoic acid C3H6ClCO2H in a 0.54mM aqueous solution of the stuff. You may find some useful data in the ALEKS Data resource. Round your answer to 2 significant digits.

Answer 1

The percent dissociation of 4-chlorobutanoic acid in a 0.54mM aqueous solution can be calculated using the equilibrium constant expression.

Step-by-step explanation:

The percent dissociation of 4-chlorobutanoic acid in a 0.54mM aqueous solution can be calculated using the equilibrium constant expression. Let's assume the initial concentration of 4-chlorobutanoic acid is [C3H6ClCO2H] and the concentration of the dissociated ions is [C3H5ClCO2-]. The equilibrium constant (K) can be expressed as:

K = [C3H5ClCO2-] / [C3H6ClCO2H]

Since the percent dissociation is the fraction of acid ionized multiplied by 100, we can solve for the percent dissociation using the equilibrium constant expression:

Percent dissociation = ( [C3H5ClCO2-] / [C3H6ClCO2H] ) * 100%