Question

A 110.0-g sample of metal at 82.00°C is added to 110.0 g of H O(l) at 27.00°C in an insulated container. The temperature rises to 30.56°C. Neglecting the heat capacity of the container, what is the specific heat of the metal? The specific heat of H O(l) is 4.18 J/(g ∙ °C).

Answer 1

`c_(p, sample) = 0.290\,(kJ)/(kg\cdot ^(\textdegree)C)`

Step-by-step explanation:

The heat rejected by the sample is equal to the heat received by the water. Then:

`-Q_(sample) = Q_(water)`

`-(0.11\,kg)\cdot c_(p.sample) \cdot (30.56\,^(\textdegree)C-82\,^(\textdegree)C) = (0.11\,kg)\cdot (4.186\,(kJ)/(kg\cdot ^(\textdegree)C) )\cdot (30.56\,^(\textdegree)C-27\,^(\textdegree)C)`

The specific heat of the sample is:

`c_(p, sample) = 0.290\,(kJ)/(kg\cdot ^(\textdegree)C)`