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Can you please help?

Can you please help?-example-1
User Pram
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1 Answer

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Answer:

The answer to your question is below

Step-by-step explanation:

3.-

[HF] = 6.9 N

Volume = ?

[H₃PO₄] = 3.2 N

Volume = 22ml

[HF] x Volume a = [H₃PO₄] x Volume b

Volume a = [H₃PO₄] x Volume b / [HF]

Volume a = 3.2 x 22 / 6.9

= 10.2 ml

4.-

[Al(OH)₃] = 4 N

Volume b = 72 ml

[HBr] = ?

Volume a = 21 ml

[Al(OH)₃] x Volume b = [HBr] x Volume a

[HBr] = [Al(OH)₃] x Volume b / Volume a

[HBr] = 4 x 72 / 21

[HBr] = 13.7 N

5.-

[HC₂H₃O₂] = 0.769 N

Volume a = ?

[Mg(OH)₂] = 1.15 N

Volume b = 31 ml

[HC₂H₃O₂] x Volume a = [Mg(OH)₂] x Volume b

Volume a = [Mg(OH)₂] x Volume b / [HC₂H₃O₂]

Volume a = 1.15 x 31 / 0.769

Volume a = 46.4 ml

X

Volume a = ?

[HCl] = 4.7 N

Volume b = 15.78 ml

[Ba(OH)₂] = 5.67 N

[HCl] x volume a = [Ba(OH)₂] x volume b

Volume a = [Ba(OH)₂] x volume b / [HCl]

Volume a = 5.67 x 15.78 / 4.7

Volume a = 19 ml

User Koxzi
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