Answer:
496 g
Step-by-step explanation:
Let's consider the reaction between ethanol and oxygen to form acetic acid and water.
CH₃CH₂OH + O₂ → CH₃COOH + H₂O
The molar ratio of CH₃CH₂OH to CH₃COOH is 1:1. The moles of acetic acid produced by the reaction of 8.26 moles of ethanol are:
8.26 mol CH₃CH₂OH × (1 mol CH₃COOH/1 mol CH₃CH₂OH) = 8.26 mol CH₃COOH
The molar mass of acetic acid is 60.05 g/mol. The mass corresponding to 8.26 moles is:
8.26 mol × 60.05 g/mol = 496 g