Question

How many seconds does it take to deposit 0.94 g of Ni on a decorative drawer handle when 14.9 A is passed through a Ni(NO3)2 solution? Molar mass of Ni is 58.69 g/mole. Faraday constant=96485 C/mole. Enter numbers into 1 decimal places.

Answer 1

Time take to deposit Ni is 259.02 sec.

Step-by-step explanation:

Given:

Current
`I = 14.9` A

Faraday constant
`= 96485`
`(C)/(mole)`

Molar mass of Ni
`= 58.69`
`(g)/(mole)`

Mass of Ni
`= 0.94` g

First find the no. moles in Ni solution,

Moles of Ni
`= (0.94)/(58.69)`

`= 0.02` mol

From the below reaction,

`Ni^(2+) + 2e` ⇆
`Ni_((s))`

Above reaction shows "1 mol of
`Ni^(2+)` requires 2 mol of electron to form 1 mol of
`Ni_((s))` "

So for finding charge flow in this reaction we write,

`=`
`0.02 * (2 )/(1 ) * 96485 (C)/(mol)`

Charge flow
`= 3859.4` C

For finding time of reaction,

`I = (q)/(t)`

Where
`q =` charge flow

`t = (q)/(I)`

`t = (3859.4)/(14.9)`

`t = 259.02` sec

Therefore, time take to deposit Ni is 259.02 sec.