Question

. Sulfur dioxide can be produced in the laboratory by the reaction of hydrochloric acid and a sulfite salt such as sodium sulfite. Na2SO3 2HCl £ 2NaCl SO2 H2O What mass of SO2 can be made from 25.0 g of Na2SO3 and 22.0 g of HCl?

Answer 1

Mass of SO₂ can be made from 25.0 g of Na₂SO₃ and 22 g of HCl = 12.672 g

Step-by-step explanation:

SO₂( sulfur dioxide) can be produced in the lab. by the reaction of hydrochloric acid & sulphite salt such as sodium.

the balanced chemical equation is as follows

Na₂SO₃ + 2 HCl → 2 NaCl + SO₂ + H₂O

Moles of Na₂SO₃ =
`(Mass)/(Molecular mass) =(25)/(126) = 0.198`

Moles of HCl =
`(mass)/(molecular mass)=(22)/(36.5)= 0.6`

using mole ratio method to find limiting reagent

For sodium sulfite
`(mole)/(stoichiometry) = (0.198)/(1)= 0.198`

for HCl
`(mole)/(stoichiometry) = (0.6)/(2)= 0.3`

since sodium sulfite is limiting reactant for above chemical reaction

1 mole of Na₂SO₃ produce 1 mole of SO₂

0.198 mole of Na₂SO₃ produce 0.198 mole of SO₂

∴ Mass of SO₂ produce = mole x molar mass of SO₂

= 0.198 x 64

= 12.672 g