14.3k views
5 votes
Cara is playing a number game where she has two tiles for each number 0 to 9. A tile is chosen at random. How many favorable outcomes are there for choosing a multiple of 3?

User Neteru
by
6.4k points

1 Answer

6 votes

If a card is chosen at random, there are 3 possible favorable outcomes for choosing a multiple of 3.

Explanation:

The number of possible numbers on the tile are:

0, 1 , 2 , 3 , 4, 5, 6, 7 , 8 and 9.

Now, the chosen tile can have any of the ten options mentioned above.

The favorable outcomes are 3 , 6 and 9 as they are the multiple of 3.

So, the number of possible favorable outcomes = 3 ways

Hence, if a card is chosen at random, there are 3 possible favorable outcomes for choosing a multiple of 3.

User Chrx
by
6.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.