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Find the general form of the equation for the quadratic that passes through the points (2,5) and (4,10)

User Hesam
by
4.2k points

1 Answer

1 vote

Answer:

The answer to your question is 5x - 2y = 0

Explanation:

Data

A (2, 5)

B (4, 10)

Process

1.- Determina the slope of the line

slope = m = (y2 - y1) / (x2 - x1)

x1 = 2 y1 = 5 x2 = 4 y2 = 10

-Substitution

m = (10 - 5) / (4 - 2)

-Simplification

m = 5/2

2.- Find the equation of the line in the general form

y - y1 = m(x - x1)

-Substitution

y - 5 = 5/2(x - 2)

-Simplification

2(y - 5) = 5(x - 2)

2y - 10 = 5x - 10

5x - 2y - 10 + 10 = 0

-Result

5x - 2y = 0

User Max Cruz
by
4.7k points