Question

: Citric acid, H3C6H5O7, is a triprotic acid. Consider a buffer system comprising H2C6H5O7 - and HC6H5O7 2- ions. What is the net ionic equation for the reaction that occurs when NaOH is added to a buffer containing H2C6H5O7 - and HC6H5O7 2- ?

Answer 1

Net ionic equation are as follows

`(1) H_3C_6H_5O_7 + 0H^- \rightarrow H_2C_6H_5O_7^- +H_2O \\\\ (2) H_2C_6H_5O_7^ - + OH^- \rightarrow H_C_6H_5O_7^( 2-) + H_2O \\\\ (3) HC_6H_5O_7 ^(2-) + OH^- \rightarrow C_6H_5O_7^(3-) +H_2O`

Step-by-step explanation:

Citric acid, H3C6H5O7, is a triprotic acid

he net ionic equation for the reaction that occurs when NaOH is added to a buffer containing H2C6H5O7 - and HC6H5O7 2-

Net ionic equation are as follows

`(1) H_3C_6H_5O_7 + 0H^- \rightarrow H_2C_6H_5O_7^- +H_2O \\\\ (2) H_2C_6H_5O_7^ - + OH^- \rightarrow H_C_6H_5O_7^( 2-) + H_2O \\\\ (3) HC_6H_5O_7 ^(2-) + OH^- \rightarrow C_6H_5O_7^(3-) +H_2O`

Answer 2

The Net reaction is

1. 
   `H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction`
2. 
   `H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^( 2-) + H_2O \ \ \ \ Add \ NaOH`
3. 
   `HC_6H_5O_7 ^(2-) + OH^- ---> C_6H_5O_7^(3-) +H_2O \ \ \ \ \ Add \ NaOH`

Step-by-step explanation:

From the Question we are told that the buffers are

`H_2C_6H_5O_7^ -` and
`HC_6H_5O_7 ^( 2-)`

When NaOH is added the Net ionic reaction would be

1. 
   `H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction`
2. 
   `H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^( 2-) + H_2O \ \ \ \ Add \ NaOH`
3. 
   `HC_6H_5O_7 ^(2-) + OH^- ---> C_6H_5O_7^(3-) +H_2O \ \ \ \ \ Add \ NaOH`