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Which set of ordered pairs does not represent a function?

{(-9,0), (-8,8), (-1,-8), (2,8)}
{(-6, -2),(-7,-7),(-5,-2), (-9,-8)}
{(9,6), (-3,-9),(-8, -1), (9,5)}
{(-1,-8), (4,1), (-7,-3), (-3,5)}

User PGOnTheGo
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2 Answers

3 votes

There is a rule for functions:

One input(x-value) can only have one output(y-value).

If one input has more than one output, it is not a function.

(This doesn't apply to outputs, one output can have more than one input and still be a function)

{(-9,0), (-8,8), (-1,-8), (2,8)}

This is a function because each input has only one output.

{(-6, -2),(-7,-7),(-5,-2), (-9,-8)}

This is a function because each input has only one output.

{(9,6), (-3,-9),(-8, -1), (9,5)}

This is not a function because the input 9 has more than one output. (9, 6), (9, 5)

{(-1,-8), (4,1), (-7,-3), (-3,5)}

This is a function because each input has only one output.

User Nate Rubin
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3 votes

Answer: D does not represent a function hopefully I'm correct with this

User Garnaat
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