Answer:
1.36m/s
Step-by-step explanation:
We are given that
Mass of one acrobat,
![m_1=60 kg](https://img.qammunity.org/2021/formulas/physics/college/imz9z5v7jfzsj8r0jxz8ofpu31juxr0nkv.png)
Mass of another acrobat,
![m_2=50 kg](https://img.qammunity.org/2021/formulas/physics/college/wiol1ojb9aqcd81nrcyqfruhbdv6tt0an4.png)
![v_2=-3 m/s](https://img.qammunity.org/2021/formulas/physics/college/jcm6duy80lidpdfkjzmxwnrtv4y1gq26x1.png)
![v_1=5 m/s](https://img.qammunity.org/2021/formulas/physics/college/bfgp7iims5h312n8whe3vxwg6ofpudgkaj.png)
We have to find their velocity immediately after they grab onto each other.
The collision between two acrobat is inelastic
According to law of conservation of momentum
![m_1v_1+m_2v_2=(m_1+m_2)V](https://img.qammunity.org/2021/formulas/physics/college/kp37esgyiplqenrxzaqkir3ptnuys1un8t.png)
Substitute the values
![60* 5+50(-3)=(60+50)V](https://img.qammunity.org/2021/formulas/physics/college/56brcw2ymqtilg03wovvggmz53qu064tx8.png)
![300-150=110V](https://img.qammunity.org/2021/formulas/physics/college/gbn23x9kobj6y3pkmoau26l536wo6x78dl.png)
![V=(300-150)/(110)=1.36m/s](https://img.qammunity.org/2021/formulas/physics/college/axjdwvomlwr7yi2imapiegnj53j7xv0dmb.png)