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5. Find the equation of the line that goes through the point (2.-3) and has a slope of -1.

y = -x-1
y = -x-3
y=2x-3
y=-x+2

6. Find the equation of the line that goes through the point (5.1) and has a slope of 0.
y = 5x + 1
y=5
y=1
x=5

2 Answers

10 votes

Answer:

A and C.

Explanation:

User Paulo Alexandre
by
8.3k points
5 votes

Answer:

  1. Option A
  2. Option C

Solution:

  • First, let's write the equation of the line in point-slope form:
  • y-y1=m(x-x1)
  • y-(-3)=-1(x-2)
  • y+3=-(x-2)
  • y+3=-x+2
  • y=-x=2-3
  • y=-x-1
  • Same with the next equation:
  • y-1=0(x-5)
  • y-1=0x-0
  • y=1

Hope it helps.

Do comment if you have any query.

User Maxim Rahlis
by
8.2k points

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