Question

Assume a reaction takes 7.5 moles of anhydrous calcium chloride and energy transfer occurs, which we record as 21.2 joules of energy. Find the heat of solution in J/mol and round to two places after the decimal point.

Answer 1

Heat of solution; ΔH = 2.83 J/mol

Step-by-step explanation:

We are given;

Number of moles; n = 7.5 moles

Energy absorbed; q = 21.2 J

Now, in endothermic reactions,

ΔH = q/n

Where ;

ΔH is heat of solution

q is amount of energy absorbed

n is number of moles of solute

Thus, plugging in relevant values, we have;

ΔH = q/n

ΔH = 21.2/7.5

ΔH = 2.83 J/mol

Answer 2

Answer: 2.83 J/mol

Step-by-step explanation:

Heat of solution, sometimes interchangeably called enthalpy of solution, is said to be the energy released or absorbed when the solute dissolves in the solvent. A solute is that which can dissolve in a solvent, to form a solution

Given

No of moles of CaCl = 7.5 mol

Total energy used = 21.2 J

Heat of solution = q/n where

q = total energy

n = number of moles

Heat of solution = 21.2 / 7.5

Heat of solution = 2.83 J/mol