Question

A sample of ideal gas is heated in a 2L vessel at a temperature of 320 Kelvin. the pressure in the vessel is 2.5 atm. What is the new pressure in the vessel if the volume is halved and the temperature is reduced to 250 Kelvin?

Answer 1

Pressure=3.91atm

Step-by-step explanation:

As given in the question that gas is ideal so

we can use Ideal gas equation

`PV=nRT`

volume of gas is not given directly but volume of container is given and we know gas takes the volume in which they are kept.

therefore mole remains contant

P1=2.5 atm

V1=2L

T1=320K

P1=?

V1=1L

T1=250K

`2.5* 2V=nR * 320`..............(1)

`P* V=nR * 250`................(2)

eqn2/eqn1

`(P)/(2.5) * (1)/(2) =(250)/(320)`

Pressure=3.91atm