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4. Find the equation of the line that goes through the point (1.-1) and has a siope of 5. y=x+5 y = 5x-1 y = 5x+1 y = 51-6
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Jun 2, 2023
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4. Find the equation of the line that goes through the point (1.-1) and has a siope of 5.
y=x+5
y = 5x-1
y = 5x+1
y = 51-6
Mathematics
high-school
Mahdi Amrollahi
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Mahdi Amrollahi
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Answer:
y=5x-6
Solution:
First, let's write the equation of the line in Point-Slope Form:
y-y1=m(x-x1)
y-(-1)=5(x-1)
y+1=5(x-1
Convert into slope-intercept:
y+1=5x-5
y=5x-5-1
y=5x-6
Hope it helps.
Do comment if you have any query.
Rohan Das
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Jun 7, 2023
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Rohan Das
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