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4. Find the equation of the line that goes through the point (1.-1) and has a siope of 5. y=x+5 y = 5x-1 y = 5x+1 y = 51-6
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4. Find the equation of the line that goes through the point (1.-1) and has a siope of 5.

y=x+5
y = 5x-1
y = 5x+1
y = 51-6

User Mahdi Amrollahi
by
3.8k points

1 Answer

5 votes

Answer:

y=5x-6

Solution:

  • First, let's write the equation of the line in Point-Slope Form:
  • y-y1=m(x-x1)
  • y-(-1)=5(x-1)
  • y+1=5(x-1
  • Convert into slope-intercept:
  • y+1=5x-5
  • y=5x-5-1
  • y=5x-6

Hope it helps.

Do comment if you have any query.

User Rohan Das
by
4.4k points
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