Answer:
Option B ⇒ Ha: mufsu - muf > 0
Explanation:
Based on the question given, the two categories of students under consideration are UF and FSU. Also, a sample of 100 students is taken from schools UF and FSU.
Let us denote the mean number of text messages sent per day at UF population by {\mu _f}μf , and denote the mean number of text messages sent per day at FSU population by {\mu _{fsu}}μfsu.
The alternative hypothesis for the difference of the means of the two populations must be stated since two populations are considered.
The alternative hypothesis is obtained as shown below:
From the information given, the UF students do take less time for texting in contrast to the FSU students. Since the UF students take less time than FSU, the difference between the mean of FSU and the mean of UF must be greater than zero.
The alternative hypothesis is,
{H_a}:{\mu _{fsu}} - {\mu _f} > 0Ha:μfsu−μf>0
Option B is the correct answer.