Answer: 62.86 dm3
Step-by-step explanation:
Given that:
Volume of water V = ?
Temperature T = 15°C
Convert Celsius to Kelvin
(15°C + 273 = 288K)
Pressure P = 125000 Pa
Convert pressure in Pascal to atmosphere,
If 101,325 Pascal = 1 atm
125000 Pascal = Z
To get Z, cross multiply
Z x 101325 Pa = 125000 Pa x 1 atm
Z = 125000 Pa / 101325 Pa
Z = 1.23 atm
Number of moles of gas = 3.27
Molar gas constant R is a constant with a value of 0.0821 atm dm3 K-1 mol-1
Then, apply ideal gas equation
pV = nRT
1.23atm x V = 3.27 moles x (0.0821 atm dm3 K-1 mol-1 x 288K)
1.23atm x V = 77.32 atm dm3
V = (77.32 atm dm3 / 1.23 atm)
V = 62.86 dm3
Thus, the volume of the gas is 62.86 dm3